5x^2+32=-28x

Solution for 5x^2+32=-28x equation:

5x^2+32=-28x

We move all terms to the left:

5x^2+32-(-28x)=0

We get rid of parentheses

5x^2+28x+32=0

a = 5; b = 28; c = +32;
Δ = b2-4ac
Δ = 282-4·5·32
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-12}{2*5}=\frac{-40}{10}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+12}{2*5}=\frac{-16}{10}
=-1+3/5
$